7x^2-8x-8=2

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Solution for 7x^2-8x-8=2 equation:



7x^2-8x-8=2
We move all terms to the left:
7x^2-8x-8-(2)=0
We add all the numbers together, and all the variables
7x^2-8x-10=0
a = 7; b = -8; c = -10;
Δ = b2-4ac
Δ = -82-4·7·(-10)
Δ = 344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{344}=\sqrt{4*86}=\sqrt{4}*\sqrt{86}=2\sqrt{86}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{86}}{2*7}=\frac{8-2\sqrt{86}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{86}}{2*7}=\frac{8+2\sqrt{86}}{14} $

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